Print Spiral Pattern in Java
Programming is always a fun and creative task. The more creative you can think the better programmer you will become. However, programming isn’t always about solving problems sometimes there’s also a fun aspect to it which makes it way more satisfying. If you are a programmer then you might have already played with patterns, strings, etc multiple times. Well, it’s also likely that you are already familiar with printing patterns. So in today’s article, we will create a program to Print Spiral Pattern in Java. With the help of this program, you will be able to print a spiral pattern of integers using java language. Practising these types of questions also helps to get an upper edge in Competitive Programming
So open up your IDE and let’s get started real quick. Once you understand the logic practice this program on your own to make your brain work in a problem-solving way. This is a somewhat hard question you might get asked in an interview so make sure to practice it on your own after reading this article.
Also Read: How To Print Hello World in Java Without Semicolon
What’s The Approach?
Firstly we will create a 2D array with size n.
Next, we will create variables to store the boundary of array and size left to print the spiral.
Also, we are going to create a char variable to store the movement of the spiral pattern. It is like ‘r’ for right, ‘l’ for left, ‘d’ for down, and ‘u’ for up.
Now we will execute a loop from 1 to n*2 and will fill up the array in a spiral pattern.
Java Program To Print Spiral Pattern
Input: n = 5
public class TechDecodeTutorials {
public static void printSpiral(int size)
{
// Create row and col
// to traverse rows and columns
int row = 0, col = 0;
int boundary = size - 1;
int sizeLeft = size - 1;
int flag = 1;
// Variable to determine the movement
// r = right, l = left, d = down, u = upper
char move = 'r';
// Array for matrix
int matrix[][] = new int[size][size];
for (int i = 1; i < size * size + 1; i++) {
// Assign the value
matrix[row][col] = i;
// switch-case to determine the next index
switch (move) {
// If right, go right
case 'r':
col += 1;
break;
// if left, go left
case 'l':
col -= 1;
break;
// if up, go up
case 'u':
row -= 1;
break;
// if down, go down
case 'd':
row += 1;
break;
}
// Check if the matrix
// has reached array boundary
if (i == boundary) {
// Add the left size for the next boundary
boundary += sizeLeft;
// If 2 rotations has been made,
// decrease the size left by 1
if (flag != 2) {
flag = 2;
}
else {
flag = 1;
sizeLeft -= 1;
}
// switch-case to rotate the movement
switch (move) {
// if right, rotate to down
case 'r':
move = 'd';
break;
// if down, rotate to left
case 'd':
move = 'l';
break;
// if left, rotate to up
case 'l':
move = 'u';
break;
// if up, rotate to right
case 'u':
move = 'r';
break;
}
}
}
// Print the matrix
for (row = 0; row < size; row++) {
for (col = 0; col < size; col++) {
int n = matrix[row][col];
System.out.print((n < 10)
? (n + " ")
: (n + " "));
}
System.out.println();
}
}
// Driver Code
public static void main(String[] args)
{
// Get the size of size
int size = 5;
// Print the Spiral Pattern
printSpiral(size);
}
}
Output:
1 2 3 4 5 16 17 18 19 6 15 24 25 20 7 14 23 22 21 8 13 12 11 10 9

